问题
解答题
已知Sn=1+
|
答案
证明:(1)当n=2时,左边=1+
+1 2
+1 3
=1 4
,右边=1+25 12
=2,2 2
∴左边>右边
(2)假设n=k(k≥2)时不等式成立,即
=1+S 2k
+1 2
+1 3
+…+1 4
≥1+1 2k
,k 2
当n=k+1时,不等式左边S2(k+1)=1+
+1 2
+1 3
+…+1 4
+…+1 2k+1 1 2k+1
>1+
+k 2
+…+1 2k+1
>1+1 2k+1
+k 2
=1+2k 2k+2k
+k 2
=1+1 2
,k+1 2
综上(1)(2)可知S2n>1+
对于任意的n≥2正整数成立.n 2