问题 填空题 若x-1x+1=ax2-1,则a=______,其中x满足的条件是______. 答案 根据题意得:a=(x-1)(x2-1)x+1=(x-1)(x+1)(x-1)x+1=(x-1)2,其中x满足的条件是:x+1≠0且x2-1≠0,解得:x≠±1.