一质量为m的物体在水平恒力F的作用下沿水平面运动，在to时刻撤去F，其v－t图象如图所示．已知物体与水平面间的动摩擦因数为μ，则下列关于F的大小及其做的功W的大小关系式中，正确的是( )
A．F＝μmg
B．F＝2μmg
C．W＝μmgvoto
D．W＝
μmgvoto
答案：D
题目分析：在加速运动过程中由牛顿第二定律可知
，在撤去拉力只剩摩擦力后
，由以上两个式子联立可知拉力F=3μmg，AB错；速度时间图像中图线所围成的面积表示位移的大小，由此可知拉力施加作用的过程中位移为
，所以拉力做功W＝
μmgvoto，D对；
点评：明确加速过程和减速过程的受力情况，速度时间图像中图线的斜率表示加速度大小，图线的面积表示位移的大小，灵活应用动能定理选择合适的研究过程，本题难度中等
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