问题 填空题
已知f(x)=
x
1-x
,设f1(x)=f(x),fn(x)=fn-1[fn-1(x)](n>1,n∈N*),则f3(x)的表达式为______,猜想fn(x)(n∈N*)的表达式为______.
答案

f1(x)=

x
1-x
f2(x)=f1[f1(x)]=
f1(x)
1-f1(x)
=
x
1-x
1-
x
1-x
=
x
1-2x
f3(x)=f2[f2(x)]=
f2(x)
1-2f2(x)
=
x
1-2x
1-2•
x
1-2x
=
x
1-22x

猜想fn(x)=

x
1-2n-1x

故答案为:

x
1-22x
x
1-2n-1x

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