问题
解答题
已知x=by+cz,y=cz+ax,z=ax+by,且x+y+z≠0. (1)试用x,y,z这3个字母表示a; (不能出现字母b,c) (2)试说明:
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答案
(1)解方程组:
,x=by+cz(1) y=cz+ax(2) z=ax+by(3)
(2)+(3)-(1)得:y+z-x=2ax,
∴a=
.y+z-x 2x
(2)由(1)得:
=a 1+a
,y+z-x x+y+z
同理可得,
=b 1+b
,x+z-y x+y+z
=c 1+c
,x+y-z x+y+z
∴
+a 1+a
+b 1+b
=c 1+c
=1.x+y+z x+y+z